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5x^2-32x=-8
We move all terms to the left:
5x^2-32x-(-8)=0
We add all the numbers together, and all the variables
5x^2-32x+8=0
a = 5; b = -32; c = +8;
Δ = b2-4ac
Δ = -322-4·5·8
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-12\sqrt{6}}{2*5}=\frac{32-12\sqrt{6}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+12\sqrt{6}}{2*5}=\frac{32+12\sqrt{6}}{10} $
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